목록문자열 (3)

요깨비's LAB

[백준, 문자열, Kotlin] P.17413 단어 뒤집기2

import java.util.* fun main() { val scr = Scanner(System.`in`) var str = scr.nextLine(); var len = str.length var idx = 0 var startIdx = 0 var endIdx = 0 var result = "" var substr = "" var findIdx = 0 while(idx < len) { if(str[0] == '') substr = str.substring(0, findIdx + 1) result += substr str = str.substring(findIdx + 1) len = str.length } else { findIdx = str.indexOfFirst { it == '
알고리즘(Kotlin)/문자열처리 2021. 9. 3. 01:00
[백준, Brute-force, Kotlin] P.9093 단어뒤집기

import java.util.* fun main() { val scr = Scanner(System.`in`) val T = scr.nextInt() scr.nextLine() val sb = StringBuffer() for(i in 0 until T) { val str = scr.nextLine() val elements = str.split(" ") for(element in elements) { sb.append(element.reversed() + " ") } sb.append("\n") } print(sb.toString()) }
알고리즘(Kotlin)/Brute-Force 2021. 5. 28. 12:38
[프로그래머스, Kotlin] 문자열 압축

import java.util.* class Solution { fun solution(s: String): Int { var answer = Int.MAX_VALUE var strLen = s.length var compactIndex = strLen / 2 var compareStr = s.substring(compactIndex, strLen) for (i in 1..compactIndex) { var resultStr = "" var index = 0 while (index strLen) break; compareStr = s.substring(index, index + i) } if (count > 1) { subStr = StringBuffer().append(count).append(subS..
알고리즘(Kotlin)/Brute-Force 2021. 3. 25. 20:22
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